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216-3x^2=3x^2
We move all terms to the left:
216-3x^2-(3x^2)=0
We add all the numbers together, and all the variables
-6x^2+216=0
a = -6; b = 0; c = +216;
Δ = b2-4ac
Δ = 02-4·(-6)·216
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-6}=\frac{-72}{-12} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-6}=\frac{72}{-12} =-6 $
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